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GRE QUANT DATABASE(UPDATED TILL JULY 21ST' 10)
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Quant.Database



Joined: 04 Sep 2009
Posts: 67

PostPosted: Thu Jul 22, 2010 10:00 am    Post subject: GRE QUANT DATABASE(UPDATED TILL JULY 21ST' 10) Reply with quote


Quant:

1. What is the probability that number selected between 1 to 350 inclusive is from 337 to 350 inclusive?
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2. If y * (0.365) = 1, then what is the value of y^2-1?


3. Col A: 6/(3^0.5)
Col B: 2*(3^0.5)


4.

What is the value of x and y in terms of ‘k’?


5. Given that 10^(-n) = 0.0001. Find the value of n?
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6.

Given two circular swimming pools each of radius 3 meters, if the centre of each circle is on the circumference of other circle, find the perimeter of the swimming pool?
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7. Given the volume of a cylinder A as (1/3)*(π)*(r^2)*(h).
Col A: The volume of cylinder B whose radius is 2r and height is 2h
Col B: 8(The volume of cylinder A)
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8.

Col A: Angle BAC
Col B: 60°
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9. Col A: The product of prime factors of 30
Col B: xxx(some value)
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therani.arch



Joined: 19 Jul 2010
Posts: 65

PostPosted: Thu Jul 22, 2010 3:04 pm    Post subject: Reply with quote


1. 1/25
2. Something <8
3. C
4. bk/a, a-k
5. 4
6.
7. A (If that is 'pie' not 'n')
8. B
9 Col A=30, Col B=?

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devineni



Joined: 21 Jul 2010
Posts: 5

PostPosted: Thu Jul 22, 2010 5:19 pm    Post subject: 4rth ans Reply with quote


hii brother
can u explain how u got x= bk/a for the 4rth question
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Devineni

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devineni



Joined: 21 Jul 2010
Posts: 5

PostPosted: Thu Jul 22, 2010 5:27 pm    Post subject: Reply with quote


7th question ans will be C
if n= constant or pie

1/3 * n * (2r)^2 * 2h = 8/3*n* r*h = A
8*(cylinder A volume) =B

both the values are equal so answer is C
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Devineni

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devineni



Joined: 21 Jul 2010
Posts: 5

PostPosted: Thu Jul 22, 2010 5:31 pm    Post subject: Reply with quote


can u explain the 8 question
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Devineni

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therani.arch



Joined: 19 Jul 2010
Posts: 65

PostPosted: Fri Jul 23, 2010 3:49 am    Post subject: Reply with quote


Hi devineni,

For the forth one, i equated the angle of both the triangle, so that makes it
k/x = (a-k)/(b-x)

Solving this you can find the answer.
P.S: 'x' is the value of x-coordinate.

For the Seventh one,
The volume of cylinder is (pie*r^2*h), for cone is 1/3*(pie*r^2*h)

For the 8th one,
No one side of the triangle is greater than sum of 2 other sides, Hence the side AC is <9.
That makes it lesser than other 2 angles of triangle ABC.
which means <60

Cheers

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rangu.naveenkumar



Joined: 18 Jul 2010
Posts: 2
Location: Hyderabad

PostPosted: Fri Jul 23, 2010 10:59 am    Post subject: Reply with quote


please explain me 6th problem....

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nehareddy4u



Joined: 23 Jul 2010
Posts: 66

PostPosted: Fri Jul 23, 2010 3:26 pm    Post subject: Reply with quote


1. 1/25

2. 6.29 (approx) or (<7)

3. C

4. any one explain it.. i got only the 'y' point

5. 4

6. 8 pi

7. D

8. A

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therani.arch



Joined: 19 Jul 2010
Posts: 65

PostPosted: Fri Jul 23, 2010 3:55 pm    Post subject: Reply with quote


Hi nehareddy4u,

Could you explain the 6th one.

Thanks

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prabudhakshin



Joined: 21 Jul 2010
Posts: 2

PostPosted: Fri Jul 23, 2010 6:43 pm    Post subject: Reply with quote


therani.arch wrote:
Hi nehareddy4u,

Could you explain the 6th one.

Thanks


The idea is u got to find the length of the arc and subtract from the perimeter of the circle.

1. Draw a line connecting the centres of the circle (call it as BASE line)
2. From one of the centre, draw two lines(length = radius = 3) to each of the intersections (where circles intersect) - call it as LINE
3. From one of the intersection point, draw perpendicular line to the BASE line - it will divide the BASE into two equal halves (1.5 each)
4. Now, cos theta = 1.5/3 = 1/2 => theta = 60 degree
5. So LINE makes 60 deg with the BASE
6. So the length of the arc = ((2 * pi * 3)/360) * 120 = 2 pi
7. Length of the other arc = 2 pi
8. Circum = (2 * pi * 3) + (2 * pi * 3) - (2 *pi) - (2* pi)

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therani.arch



Joined: 19 Jul 2010
Posts: 65

PostPosted: Fri Jul 23, 2010 7:12 pm    Post subject: Reply with quote


Got it.
Thanks a lot

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sunil24sunil



Joined: 17 Jul 2010
Posts: 1

PostPosted: Mon Jul 26, 2010 11:30 am    Post subject: 6th questionnnnn answer Reply with quote


therani.arch wrote:
Got it.
Thanks a lot







6*pi + 6*pi - 3/2*pi-3/2*pi = 9*pi

pakkkkkkkkkkkaaaaaaaaa solution i think any doubts post messageeee

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nandana



Joined: 18 Jul 2010
Posts: 6

PostPosted: Mon Jul 26, 2010 3:13 pm    Post subject: Reply with quote


can anyone can exlain 1st que

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nandana



Joined: 18 Jul 2010
Posts: 6

PostPosted: Mon Jul 26, 2010 3:36 pm    Post subject: Reply with quote


can u xplain 6que

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nehareddy4u



Joined: 23 Jul 2010
Posts: 66

PostPosted: Thu Jul 29, 2010 4:53 pm    Post subject: Reply with quote


nandana wrote:
can u xplain 6que



2 circles with radius 3..

so the distance between the two centers will aslo be 3...
draw a line..

next.. draw a line from the center to the upper intersection of the circles.. which length is 3 (i.e.. since radius).. similarly with the 2nd circle also..
now it forms a equilateral triangle.. v know angle is 60'.. so find the length of the arc with angel as 60' and radius as 3.. u will get (pi).. there are 4 pi..

so total circumference - 4 pi.. ==> 8pi..

total circumference of 2 circles = 2(pi)(3) + 2(pi)(3) ==> 12 pi..

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